A light particle moving horizontally with a speed $v_1$ strikes a very heavy block moving in the same direction with a speed $v_2$. The collision is elastic. After the collision, the velocity of particle is :-
$2v_1 -v_2$ in original direction
$v_1 -v_2$ in original direction
$v_2 -2v_1$ in original direction
$2v_2 -v_1$ in original direction
Body of mass $M$ is much heavier than the other body of mass $m$. The heavier body with speed $v$ collides with the lighter body which was at rest initially elastically. The speed of lighter body after collision is
A ball of mass $m$ suspended from a rigid support by an inextensible massless string is released from a height $h$ above its lowest point. At its lowest point, it collides elastically with a block of mass $2 m$ at rest on a frictionless surface. Neglect the dimensions of the ball and the block. After the collision, the ball rises to a maximum height of
A body of mass $m$ moving with velocity $v$ elastic collides head on with another body of mass $2\,\,m$ which is initially at rest. The ratio of $K.E.$ of the colliding body before and after collision will be
Body $A$ of mass $4 \;\mathrm{m}$ moung with speed $u$ collides with another body $B$ of mass $2\; \mathrm{m}$, at rest. The collision is head on and elastic in nature. After the collision the fraction of energy lost by the colliding body $A$ is
A spring-block system is resting on a frictionless floor as shown in the figure. The spring constant is $2.0 N m ^{-1}$ and the mass of the block is $2.0 kg$. Ignore the mass of the spring. Initially the spring is in an unstretched condition. Another block of mass $1.0 kg$ moving with a speed of $2.0 m s ^{-1}$ collides elastically with the first block. The collision is such that the $2.0 kg$ block does not hit the wall. The distance, in metres, between the two blocks when the spring returns to its unstretched position for the first time after the collision is. . . . . .